1860 United States presidential election in Florida
Election in Florida
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 County Results
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The 1860 United States presidential election in Florida took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose three electors of the Electoral College, who voted for president and vice president.
Florida was won by Southern Democratic candidate John C. Breckinridge, who won the state by a margin of 26.13%.
Republican Party candidate Abraham Lincoln was not on the ballot in the state.
This was the last presidential election Florida would participate in until the 1868 election due to the American Civil War and the beginnings of the Reconstruction Era.
Results
| 1860 United States presidential election in Florida[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Southern Democratic | John Cabell Breckinridge of Kentucky | Joseph Lane of Oregon | 8,277 | 62.23% | 3 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 4,801 | 36.10% | 0 | 0.00% | ||
| Democratic | Stephen Arnold Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 223 | 1.68% | 0 | 0.00% | ||
| Total | 13,301 | 100.00% | 3 | 100.00% | ||||
See also
- United States presidential elections in Florida
- 1860 United States House of Representatives election in Florida
- 1860 Florida Gubernatorial election
References
- ^ "1860 Presidential General Election Results - Florida".
State results of the 1860 U.S. presidential election | ||
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